Explain atomic radius of elements of boron family.
On moving down the group, for each successive member one extra shell of electrons is added and, therefore, atomic radius is expected to increase.
However, a deviation can be seen. Atomic radius of $Ga$ is less than that of Al. This can be understood from the variation in the inner core of the electronic configuration.
The presence of additional $10 d$-electrons offer only poor screening effect for the outer
electrons from the increased nuclear charge in gallium. Consequently, the atomic radius of gallium ($135 pm$) is less than that of aluminium ($143 pm$).
However, regular periodicity is observed in case of ionic radius.
The liquefied metal which expands on solidification is
Suggest reasons why the $B-F$ bond lengths in $BF_3\, (130\, pm)$ and $BF_4^- \,(143\, pm)$ differ.
The Lewis acid character of boron tri halides follows the order:
$2 {X}+\mathrm{B}_2 \mathrm{H}_6 \rightarrow\left\lfloor\mathrm{BH}_2(\mathbf{X})_2\right\rfloor^{+}\left\lfloor\mathrm{BH}_4\right]^{-}$ the amine(s) ${X}$ is$(are)$
$(A)$ $\mathrm{NH}_3$ $(B)$ $\mathrm{CH}_3 \mathrm{NH}_2$ $(C)$ $\left(\mathrm{CH}_3\right)_2 \mathrm{NH}$ $(D)$ $\left(\mathrm{CH}_3\right)_3 \mathrm{~N}$
The electrochemical extraction of aluminum from bauxite ore involves.
$(A)$ the reaction of $Al _2 O _3$ with coke ($C$) at a temperature $>2500^{\circ} C$.
$(B)$ the neutralization of aluminate solution by passing $CO _2$ gas to precipitate hydrated alumina $\left( Al _2 O _3 .3 H _2 O \right)$
$(C)$ the dissolution of $Al _2 O _3$ in hot aqueous $NaOH$.
$(D)$ the electrolysis of $Al _2 O _3$ mixed with $Na _3 AlF _6$ to give $Al$ and $CO _2$.